We need to find the area for the given figure.
Now, we can divide the figure into two rectangles:
Then, we need to find each area. The area for a rectangle is given by the next formula:
![A=Length\cdot\text{ width}](https://img.qammunity.org/2023/formulas/mathematics/college/mhm6zqsd7mpealzaq2gkogivqrgttzgxdm.png)
For the largest rectangle:
Lenght = 2yd + 5yd + 2yd
Lenght = 9yd
Width = 5yd
Therefore, the area for the largest rectangle is:
![A=9yd\cdot5yd](https://img.qammunity.org/2023/formulas/mathematics/college/b4fbbjsupq71kh2t58b1v5pusowp6wo1rz.png)
![A=45yd^2](https://img.qammunity.org/2023/formulas/mathematics/college/95cja1gdu1bkq0lh643jyr90fj0ufbc714.png)
For the small rectangle:
Length = 5yd
Width = 3yd
Therefore, the area for the small rectangle is:
![A=5yd\cdot3yd](https://img.qammunity.org/2023/formulas/mathematics/college/61xmf1tpsiujqe8zbeh0kr5n258s3umbd0.png)
![A=15yd^2](https://img.qammunity.org/2023/formulas/mathematics/college/498sk3ai1e3vv84kn6lqq6h805g4h9u0id.png)
Now, to find the total area of the figure, we need to add up to both rectangles areas:
![A_t=small\text{ rectangle +largest rectangle}](https://img.qammunity.org/2023/formulas/mathematics/college/d8lo2vl3op3i0kw805xsfpklnyhivkymo8.png)
Then:
![A_t=60yd^2](https://img.qammunity.org/2023/formulas/mathematics/college/b12zqb0l41xjxbjbd5lduzbaw4zggkv229.png)
Hence, the total area for the figure is 60yd²