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A football of mass 0.500 kg has a change of velocity of 24.0 when it is punted. If the football experiences a force of 120 N, for how long was it in contact with the punter’s foot?

User JvR
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1 Answer

4 votes

Answer: 1 second

Step-by-step explanation:

Given,

change of velocity, as in dv = 24

mass of football = 0.5kg

Force = 120 N

We need to find the difference of time as in dt

Now, dv/dt means acceleration

Also, F = ma

⇒ a = F/m

= 120/5 = 24 m/s²

Now,

dv/dt = 24

⇒ 24/dt = 24

⇒ dt = 1 s

So football was in contact with foot for 1 second

User Amasuriel
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