Answer
c) Cl⁻
Step-by-step explanation
a) Na belongs to group I, therefore, its Lewis symbol will have 1 electron
b) Si belongs to group IV, hence, it will have 4 electrons in its Lewis symbol
c) Cl⁻: Neutral Cl has 7 electrons in its valence shell and when it gains 1 electron more to become Cl⁻, then it will have 8 electrons in its Lewis structure.
d) P²⁻ will have 7 electrons in its Lewis symbol because a neutral P has 5 electrons in its valence shell and when it gains 2 electrons more to become P²⁻, its valence electrons will be 7