![3+(2+8)^2\colon4\cdot((1)/(2))^4](https://img.qammunity.org/2023/formulas/mathematics/college/b30ay9gzhvzjb4o5392nzabctu11en1nli.png)
We need to solve the expression above. To do that, the first step is to solve the operations inside the parenthesis:
![3+10^2\colon4\cdot(1)/(2^4)](https://img.qammunity.org/2023/formulas/mathematics/college/eqesu9raq1ispxheeycf1hwbauc0u3zv6b.png)
Then we need to calculate the powers.
![3+100\colon4\cdot(1)/(16)](https://img.qammunity.org/2023/formulas/mathematics/college/wq5pckxruggvqosfwkz5dr231urpcuq0gh.png)
Now we need to calculate the division.
![3+25\cdot(1)/(16)](https://img.qammunity.org/2023/formulas/mathematics/college/7h93d1l98ia3yaq075pmcplgspc71anbht.png)
We need to now perform the multiplications.
![3+(25)/(16)](https://img.qammunity.org/2023/formulas/mathematics/college/st247k56ineah3ypkzjv0hs1ivknmftaoi.png)
Finally we need to perform the sum.
![\begin{gathered} (16\cdot3+25)/(16) \\ (48+25)/(16)=(73)/(16) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4d5actlq0qab4a4k9laqma8zn55xhpuez5.png)
The result of the expression is 73/16.