Question

The momentum of a 30.0 g sparrow with a speed of 12 m/s is 0.36 kgm/s. What will be it’s momentum 12 s later if a constant 0.02 N force due to air resistance acts on it?I need the answer and the work

Answer 1

Given data

The mass of the sparrow is m = 30 g = 0.03 kg

The initial momentum on the sparrow is pi = 0.36 kgm/s

The initial speed of the sparrow is u = 12 m/s

The duration of the time interval is t = 12 s

The magnitude of the constant force is F = 0.02 N

The expression for the final momentum is given as:

`\begin{gathered} F=(p_f-p_i)/(t) \\ p_f=F* t+p_i \end{gathered}`

Substitute the value in the above equation.

`\begin{gathered} p_f=0.02\text{ N}*12\text{ s+0.36 kgm/s} \\ p_f=0.6\text{ kgm/s} \end{gathered}`

Thus, the final momentum of the sparrow is 0.6 kgm/s.