Given:
The length of the box is l = 5 inches.
The width of the box is w = 4 inches.
The height of the box is h = 3.5 inches.
The objective is to find the surface area of the box to cover with a wrapper.
Step-by-step explanation:
The general formula to find the surface area of the box is,
![\text{TSA}=2(lw+wh+lh)\text{ . . . . . . (1)}](https://img.qammunity.org/2023/formulas/mathematics/college/9jl57xc0wcagdjp3bgt5faep1cqf1g1met.png)
On plugging the given values in equation (1),
![\text{TSA}=2(5*4+4*3.5+5*3.5)](https://img.qammunity.org/2023/formulas/mathematics/college/8ijlc4u11lqldo2do336mi72rfcoabcl91.png)
On further solving the above equation,
![\begin{gathered} \text{TSA}=2(20+14+17.5) \\ =2(51.5) \\ =103in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bdpav3nhakkuv9s02mk5pewniuq6l6fqnv.png)
Hence, the required wrapping paper is 103 square inches.