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What is the electric force acting between two charges of 0.0042 C and -0.0050 C that are 0.0030 m apart?Use Fe = kq1q2/r2 and k = 9.00 x 10^9 N-m²/C².A. 2.1 x 10^10 NB. -2.1 x 10^10 NC. -6.3 x 10^7 ND. 6.3 × 10^7 N

User Lukas Ruge
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1 Answer

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Step-by-step explanation:

To find the electric force that is acting between two charges we can use the Coulomb's Law.

Fe = k * q₁ * q₂/r²

Where q₁ is quantity of charge of the charge number 1, q₂ is the quantity of charge of the charge number 2, k is the Coulomb's law constant (9.00 x 10^9 N-m²/C²) and r is the distance between the two charges. We already know these values.

q₁ = 0.0042 C

q₂ = 0.0050 C

k = 9.00 x 10^9 N-m²/C²

r = 0.0030 m

We can replace these values in the formula and get the answer to our question.

Fe = k * q₁ * q₂/r²

Fe = 9.00 x 10^9 N-m²/C² * 0.0042 C * 0.0050 C/(0.0030 m)²

Fe = 2.1 *10^10 N

Answer: a. 2.1 *10^10 N

User Sajee
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