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Hi, can you help me to solve this exercise please. If MK=6 ft, find the length “MKL to the nearest Tenth!

Hi, can you help me to solve this exercise please. If MK=6 ft, find the length “MKL-example-1
User Nanju
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1 Answer

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To find the arc length we need to know the angle subtended by the arc.

From the diagram we notice that angle MNK is of 180°.

We also notice that:


\begin{gathered} m\angle JNK+m\angle KNL=90 \\ 52+m\angle KNL=90 \\ m\angle KNL=90-52 \\ m\angle KNL=38 \end{gathered}

Then the angle subtended by the arc MKL is 218°.

Now that we know this we need to remember that the arc length is given by:


s=2\pi r((\theta)/(360))

in this case the radius is 3 ft (The radius is half the diameter) then we have that:


\begin{gathered} s=2\pi(3)((218)/(360)) \\ s=11.4 \end{gathered}

Therefore the arc length is 11.4 ft.

User Koenyn
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