We have the parabolic equation:

This equation is expressed in vertex form.
The vertex is (2,3).
As the square term is applied to the term with x, the axis of symmetry is vertical (x = 2).
We are left then with two options.
As the quadratic coefficient is positive (a = 1/12, if we rearrange the equation), the parabola opens upward.
Then, the corresponding graph is Option B:
Answer: Option B