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Question 410What is the length of line segment DK to the nearest tenth of an inch?

Question 410What is the length of line segment DK to the nearest tenth of an inch-example-1

1 Answer

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The Solution:

Given the figure below:

We are required to find the length of DK to the nearest tenth of an inch.

By the Trigonometrical Ratio, we have that:


\sin 43^o=\frac{\text{opp}}{\text{hyp}}=(16)/(DK)
\sin 43^o=(16)/(DK)

Cross multiplying, we get


DK\sin 43^o=16

Dividing both sides by sin43, we get


DK=(16)/(\sin 43^o)=23.4605\approx23.5^o

Therefore, the correct answer is 23.5 degrees.

Question 410What is the length of line segment DK to the nearest tenth of an inch-example-1
User Byte Brad
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