Given function is,
![f(x)=\sqrt[]{x}+1](https://img.qammunity.org/2023/formulas/mathematics/college/zq6qo5k02ojai63iizxku3nrejlh3ihfr6.png)
So the value for x subsituted here is -2. so we get,
![\begin{gathered} f(-2)=\sqrt[]{-2}+1 \\ f(-2)=i\sqrt[]{2}+1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/91d68hbvzo0r3irjtmw7np49882hm4k2e9.png)
So the requred answer is the function cannot have a real value, because it has a negative sign inside the root. so it is not possible for this function to have an real value output.
But the function can have an output in Imaginary value ( i ).