Question

How to solve (2d+6)(3d-15)=0

Answer 1

Given

`\mleft(2d+6\mright)\mleft(3d-15\mright)=0`

We have

`\begin{gathered} 2d+6=0 \\ or \\ 3d-15=0 \end{gathered}`

Then solve each one

`\begin{gathered} 2d+6=0 \\ 2d+6-6=0-6 \\ 2d=-6 \\ (2d)/(2)=(-6)/(2) \\ d=-3 \end{gathered}`

And

`\begin{gathered} 3d-15=0 \\ 3d-15+15=0+15 \\ 3d=15 \\ (3d)/(3)=(15)/(3) \\ d=5 \end{gathered}`

Answer: d = -3, d = 5