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Suppose that IQ scores have a a bell shaped distribution with a mean of 96 and the standard deviation of 17. Using the empirical rule what percentage of IQ scores are no more than 79 please do not round your answer

Suppose that IQ scores have a a bell shaped distribution with a mean of 96 and the-example-1

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GIVEN:

We are given that IQ scores have a bell shaped distribution with a mean of 96 and a standard deviation of 17.

Required;

Using the emperical rule, what percentage of IQ scores are no more than 79?

Step-by-step explanation;

For a bell-shaped distribution, we already know that,

68% of the data set lies within one standard deviation

95% of the data set lies within two standard deviations

99.7% of the data set lies within three standard deviations

The condition given is that the IQ scores are no more than 79, hence;


\begin{gathered} n=(79-96)/(17) \\ \\ n=(-17)/(17)=-1 \end{gathered}

Now we can see that the IQ score of 79 is 1 standard deviation to the left of the mean (that is to the left of 96).

We also take note that 68% of the data set lies within one standard deviation on either side of the mean.

Therefore, for the IQ scores to be 1 standard deviation from the mean, we would have;


\begin{gathered} (1-68\%)/(2)=(1-0.68)/(2) \\ \\ =0.16 \end{gathered}

Expressed as a percentage, we now have


1.6\%

ANSWER:

Therefore, 1.6% of IQ scores would be no more than 79.

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