Question

Pls I need the answers put it neatly labeling a and b. Thanks!

Answer 1

(a)

Given that a fair cube has four faces, a red face, a blue face, a green face and a white face.

The cube is tossed and the color that it lands on is recorded.

The cube lands on red 4 times as often as it lands on blue.

The cube lands on blue twice as often as it lands on green and it lands on green as often as it lands on white.

So, here, the red face is obtained in maximum cases.

Then comes the blue face and then the green and white face.

Let X be the number of times it lands on white, Y be the number of times it lands on green, Z be the number of times it lands on blue and W be the number of times it lands on red.

Then,

`\begin{gathered} W=4Z \\ Z=2Y \\ Y=X \end{gathered}`

Let us consider that the red is landed 16 times.

Then, blue is landed

`(16)/(4)=4\text{ times}`

Green and white is landed

`(4)/(2)=2\text{ times}`

Thus, if a cube is thrown for 24 times,

it is landed red for 16 times, blue for 4 times, green for 2 times, and white for 2 times

Thus, if the red is landed for n times, then blue is landed for

`(n)/(4)\text{ times}`

Green and white each is landed for

`(n)/(8)\text{ times}`

(b)

The bar diagram is shown below for a throw of 24 times