Question

When a pitcher throws a baseball, it reaches a top speed of 39 m/s. If thebaseball takes 1.5 seconds to travel from the pitcher to the catcher, what isits acceleration? (Assume the ball is moving at 0 m/s right before it leavesthe pitcher's hand.)A. 23 m/s2B. 17 m/s2C. 11 m/s2D. 26 m/s2

Answer 1

Given,

The final velocity of the ball, v=39 m/s

The initial velocity of the ball, u=0 m/s

The time duration, t=1.5 s

The final velocity of an object upon which an accleration, a, acts for a duration of t seconds is given by one of the equations of motion as

`v=u+at`

By substituting the known values and simplifying the resulting equation we will get the acceleration of the ball.

Thus,

`\begin{gathered} 39=0+a*1.5 \\ \Rightarrow a=(39)/(1.5) \\ 26m/s^2 \end{gathered}`

Thus the acceleration of the ball is 26 m/s²

Therefore the right answer is option 4.