Question

3(2c+d)-4(c-d)+d squared when c=1 d=3 please explain

Answer 1

We need to find the value of the expression 3(2c+d)-4(c-d)+d² when c = 1 and d = 3.

So we just need to apply those values to the variables and then calculate the expression:

`\begin{gathered} 3\left(2c+d\right)-4\left(c-d\right)+d^2 \\ 3(2\cdot1+3)-4(1-3)+3^2 \\ 3(2+3)-4(-2)+9 \\ 3\cdot5+8+9 \\ 15+8+9 \\ 32 \end{gathered}`

So the value of the expression is 32.