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A minor league baseball team plays 80 games in a season. If the team won 17 more than twice as many games as they lost, how many wins and losses did the team have?How many games did the team lose?

User Michi
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1 Answer

6 votes

We know that

• There are 80 games in total.

,

• The team won 17 more than twice as they lost.

Each statement can be expressed as an equation.


w+l=80

Because there are 80 games in total.


w=17+2l

Now, we replace the second equation in the first one.


17+2l+l=80

We solve for l


\begin{gathered} 17+3l=80 \\ 3l=80-17 \\ l=(63)/(3)=21 \end{gathered}

Therefore, the team lost 21 games.

We use this value to find the games they won.


w=17+2(21)=17+42=59

Therefore, the team won 59 games.

User Jithesh
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