Question

The pressure inside an aerosol can is 3.80 atm at 25.0°C. If the temperature is increased from 25.0°C to 100.0°C, what would be

the pressure inside the can?

A. 5.05 atm
B. 4.76 atm
C. 15.2 atm
D. 3.04 atm

Answer 1

B. 4.76 atm

Step-by-step explanation:

`P_1` = Initial pressure = 3.8 atm

`T_1` = Initial temperature =
`25+273.15\ \text{K}`

`P_2` = Final pressure

`T_2` = Final temperature =
`100+273.15\ \text{K}`

From Gay Lussac's law we have

`(P_2)/(P_1)=(T_2)/(T_1)\\\Rightarrow P_2=P_1(T_2)/(T_1)\\\Rightarrow P_2=3.8*(100+273.15)/(25+273.15)\\\Rightarrow P_2=4.76\ \text{atm}`

The pressure inside the can would be
`4.76\ \text{atm}`.