1) Mass percent
![\%=\frac{gramsofsolute_{}}{gramsofsolution}\cdot100](https://img.qammunity.org/2023/formulas/chemistry/college/hzqu7m08l9kpe4pnv1236mb47qga4xlzcr.png)
2) List known values
Sample: 0.965 kg
![g=0.965kg\cdot(1000g)/(1kg)=965g](https://img.qammunity.org/2023/formulas/chemistry/college/qit4vdqo35emqoir9lyrfalj3yrnzev99o.png)
2) Plug in known values and solve for grams of solute.
![27.3\%=\frac{\text{grams of solute}}{965\text{ g solution}}\cdot100](https://img.qammunity.org/2023/formulas/chemistry/college/gu5kkgdiuh7v4yjbj1fk77t1mju06amqtf.png)
![gSolute_{}=27.3\cdot\frac{965\text{ g solution}}{100}_{}=263.445\text{ g solution}](https://img.qammunity.org/2023/formulas/chemistry/college/wtuwsnp3zmh4gdmitj6cywg9je0m5771sz.png)
3) Convert grams of solute to moles
The molar mass of the unknown compound is 25.2 g/mol
![mol_{}=263.445g\cdot\frac{1mol_{}}{25.2g_{}}=10.45mol_{}](https://img.qammunity.org/2023/formulas/chemistry/college/tjx39u0qgif5pvlu8xznegd17nrmn8ss78.png)
There are 10.45 moles of the unknown compound present in the sample.