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Constants for waterHvap40.65 kJ/mol-285.83 kJ/mol6.03 kJ/mol4.186 J/g°CAHAHfusionspecific heatmolar mass 18.02 gHow much energy is consumed by thawing 4.3 g ice?

Constants for waterHvap40.65 kJ/mol-285.83 kJ/mol6.03 kJ/mol4.186 J/g°CAHAHfusionspecific-example-1
User Falco
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1 Answer

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INFORMATION:

Is given that

And we must find how much energy is consumed by thawing 4.3 g ice

STEP BY STEP EXPLANATION:

To find it, we need to multiply the mass of the ice by the Hfusion


4.3g*6.03(kJ)/(mol)

Since we need the energy, the answer must be in kJ. So, we need to use the molar mass to obtain the answer in kJ


4.3g*(1mol)/(18.02g)*6.03(kJ)/(mol)

Finally, when we simplify the expression, the answer will be in kJ

ANSWER:

A. 4.3 g x 1 mol/18.02 g x 6.03 kJ/mol

Constants for waterHvap40.65 kJ/mol-285.83 kJ/mol6.03 kJ/mol4.186 J/g°CAHAHfusionspecific-example-1
User K J Gor
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