Step-by-step explanation:
First, we need to transform 32.73 g of FePO4 into moles.
For this, we use the following formula: moles = mass/molar mass
molar mass of FePO4 = 150.82 g/mol
moles = 32.73/150.82
moles = 0.22 moles
Now we use the equation ratio between FePO4 and Fe2(SO4)3 to find out the quantity in moles of Fe2(SO4)3.
2FePO4 + 3Na2SO4 → Fe2(SO4)3 + 2Na3PO4
2 moles of FePO4 produces 1 moles of Fe2(SO4)3
So:
2 moles of FePO4 --- 1 moles of Fe2(SO4)3
0.22 moles of FePO4 --- x moles of Fe2(SO4)3
x = 0.11 moles of Fe2(SO4)3
Now we transform the quantity of moles of Fe2(SO4)3 into grams using the following formula: mass = moles x molar mass
molar mass of Fe2(SO4)3 = 399.88 g/mol
mass = 0.11 x 399.88
mass = 43.39 g
Answer: mass = 43.39 g