We know that:
- the sum of two consecutive numbers is 89
And we must find the two numbers
To find them, we can use equations to represent the situation.
1. We can use the next equation

Where, n is the smallest number and m is its consecutive number
2. Since m is the number after n, we can write m as

3. We must replace m = n + 1 in the first equation

4. Finally, we must replace n = 44 in the equation for m

ANSWER:
B.44 and 45