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Differentiate. y = (x2 - 2x + 6) ex O (2x - 2) et O (x2 + 4x + 4) et 0 (x² + 4) ex 03 + 4x + 6 ex 3 400

Differentiate. y = (x2 - 2x + 6) ex O (2x - 2) et O (x2 + 4x + 4) et 0 (x² + 4) ex-example-1
User Ron Lisle
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1 Answer

3 votes

y=(x^2-2x+6)e^x

Differentiate y

so,


\begin{gathered} y^(\prime)=(2x-2)\cdot e^x+(x^2-2x+6)\cdot e^x \\ y^(\prime)=(2x-2+x^2-2x+6)\cdot e^x \\ y^(\prime)=(x^2+4)\cdot e^x \end{gathered}

so, the answer is option 3

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Note: we have used the rule of y = f(x) * g(x)

y' = f'(x) * g(x) + f(x) * g'(x)

User Clay Risser
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