Answer:
the thermal energy absorbed is 46,893 J
Step-by-step explanation:
Given;
mass of the water, m = 145 g = 0.145 kg
initial temperature of the water, t₁ = 23 ⁰C
final temperature of the water, t₂ = 100 ⁰C
specific heat capacity of water, c = 4,200 J/kg.⁰C
The thermal energy absorbed is calculated as;
H = mcΔt
H = 0.145 x 4,200 x (100 - 23)
H = 46,893J
Therefore, the thermal energy absorbed is 46,893J