61.2k views
4 votes
In one revolution, how much farther does a point 10 cm from the center of the record travel than a point 3 cm from the center? Round your answer to the nearest tenth. INCLUDE A WRITTEN EXPLANATION OR HALF-CREDIT!

User Amilcar
by
4.4k points

1 Answer

3 votes

The distance that the point on the record travels can be calculated using the circumference formula:


C=2\pi r

The system described in the question can be drawn as shown below:

The circumference of Point A with a radius of 10 cm is calculated to be:


\begin{gathered} C_A=2\pi*10 \\ C_A=20\pi\text{ cm} \end{gathered}

The circumference of Point B with a radius of 3 cm is calculated to be:


\begin{gathered} C_B=2\pi*3 \\ C_B=6\pi\text{ cm} \end{gathered}

Therefore, the difference in distance is calculated to be:


\Rightarrow20\pi-6\pi=14\pi=43.98\text{ cm}

In decimals, to the nearest tenth, the answer will be 44.0 cm.

In one revolution, how much farther does a point 10 cm from the center of the record-example-1
User PalFS
by
3.5k points