Question

Solve the right triangle with b=1.97 and c= 4.16. Round off the results according to the table below

Answer 1

Hello!

To solve this exercise, we must use the Pythagoras Theorem:

So, we will have:

`\begin{gathered} c^2=a^2+b^2 \\ \end{gathered}`

Knowing it, let's replace it with the variables:

• b ,= 1.97

,

• c ,= 4.16

`\begin{gathered} 4.16^2=a^2+1.97^2 \\ 17.3056=a^2+3.8809 \\ 17.3056-3.8809=a^2 \\ a^2=13.4247 \\ a=√(13.4247) \\ a\cong3.66 \end{gathered}`

The measurement of the third side of the right triangle is approximately 3.66.