Question

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Answer 1

Ace Hardware sold 48 boxes of pens and Ace Hardware sold 240 batteries

Step-by-step explanation:

Cost for batteries = $3

Cost of small boxes of pens = $5

Total sales = $960

let number of batteries = b

number of boxes of pens = p

Cost for batteries (number of batteries) + Cost of small boxes of pens (number of boxes of pens) = Total sales

`\begin{gathered} 3(b)\text{ + 5(p) = 960} \\ 3b\text{ + 5p = 960 }\ldots.(1) \end{gathered}`

From the questions, customers bought 5 times as many batteries as boxes of pens

b = 5 times of p

`b=5p\text{ }\ldots\text{ (2)}`

Using substitution method

From equation 2, b ihas been made the subject of formula.

susbtitute for b in equation (1):

`\begin{gathered} 3(5p)\text{ + 5p = 960} \\ 15p\text{ + 5p = 960} \\ 20p\text{ = 960} \\ \\ \text{divide both sides by 20:} \\ (20p)/(20)\text{ = }(960)/(20) \\ p\text{ = 48} \end{gathered}`

substitute for p in equation (2):

`\begin{gathered} b\text{ = 5(48)} \\ b\text{ = 240} \end{gathered}`

Hence, Ace Hardware sold 48 boxes of pens and Ace Hardware sold 240 batteries