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you can determine of a line or the equation of an exponential given any two points that lie on these curves.In these excerise we will pick two special points.consider the points (0,5) and (1, 15) (a) write the equation of the line that passes between these two points in y=mx+ b form(b) write the equation of these exponential that passes between these two points in y =a(b)^x form(c) sketch two curves on the axes below .label with their equation

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Answer:

y = 10x+5

Step-by-step explanation:

a) The standard form of equation of a line is expressed as y = mx+b

m is the slope

b is the y-intecept

Given the coordinate points (0, 5) and (1, 15)

Slope m = y2-y1/x2-x1

m = 15-5/1-0

m = 10/1

m = 10

Get the y-intercept

Substitute m = 10 and the poimt (0,5) into y = mx+b

5 = 10(0) + b

5 = 0 + b

b = 5

Get the required equation;

Recall that y = mx+b

y = 10x + 5

Hence the equation of the line that passes between these two points is y = 10x+5

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