Question

A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s

when it collides with the stationary target glider. Explain what happens next.

Answer 1

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Step-by-step explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

p₀ = m v₀

celestines que clash case

p_f = (m + M) v

po = pf

m v₀ = (n + M) v

v =
`(m)/(m+M)`

calculemos

v=
`(0.200)/(0.200+M) 0.450`

v= 0.09 m/s

elastic shock case

p₀ = m v₀

p_f = m v₁ +M v₂

p₀ = p_f

m v₀ = m v₁ + m v₂