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Required 1. A capacitbör has a capacitance of 4.50 uF. What potential difference would be required to store 15.0 μC? *

User CubeJockey
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Answer:

Explanations:

The capacitance, C = 4.50 μF

The charge, Q = 15.0 μC

The relationship between the capacitance (C), charge (Q), and the potential difference (V) is given as:

Q = CV

Substitute C = 4.5 and Q = 15 into Q = CV

15 = 4.5V

V = 15/4.5

V = 3.33 Volt

The potential difference required is

User Sobhan Jahanmard
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