The general form of a linear equation in the slope-intercept form is given to be:

where m is the slope and b is the y-intercept.
The equation in the question is given to be:

To get the slope and y-intercept, we just need to make y the subject of the equation. This we can do by subtracting 4x from both sides of the equation:

That is the equation in the slope-intercept form.
Therefore, the slope and y-intercept of the equation are given to be:
