Question

A current of 1.2 A flows through a light bulb when it is connected across a 120 V source. What power is dissipated by the bulb?

Answer 1

144 Watts

Step-by-step explanation:

The power dissipated is equal to

P = IV

Where I is the current and V is the voltage. Replacing I = 1.2 A and V = 120 V, we get

P = (1.2A)(120 V)

P = 144 Watts

Therefore, the power is 144 Watts