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3x+2y=7 y=3x-19 could someone show me a step by step for this equation for substitution

User Daniel Kurz
by
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2 Answers

15 votes
15 votes

Answer:

x=5,y=-4

Explanation:

  1. [
    (3x+2y=7)/(y=3x-19)]
  2. [3x+2(3x-19)=7]
  3. [9x-38=7]
  4. y=3 · 5 - 19
  5. x=5,y=-4
User Shortduck
by
2.0k points
16 votes
16 votes

Answer:


\boxed {\boxed {\sf (5,-4)}}

Explanation:

We are given the equations:


3x+2y=7 \\y=3x-19

Since we know what y is equal to, we can substitute that expression in for y in the first equation.


3x+2(3x-19)=7

Distribute the 2. Multiply each term inside the parentheses by 2.


3x+(2*3x)+ (2*-19)=7


3x+6x+-38= 7

Combine the like terms (the terms with variables).


9x-38=7

Since we are solving for x, we must isolate the variable. 38 is being subtracted and the inverse of subtraction is addition. Add 38 to both sides.


9x-38+38=7+38 \\9x=7+38\\9x=45

Now x is being multiplied by 9. The inverse of multiplication is division. Divide both sides by 5.


9x/9=45/9\\x=45/9\\x=5

Now we know what x is equal to and can substitute the value into the second equation.


y=3x-19


y=3(5)-19

Multiply.


y=15-19

Subtract.


y= -4

Coordinate points are written as (x,y). Therefore, the solution is (5, -4).

User Mostafa Barmshory
by
2.8k points