Question

Can someone please help me solve the following?Solve for x

Answer 1

x = ± 5i

Step-by-step explanation

To solve this equation, first, we have to subtract 9 from both sides of the equation,

`\begin{gathered} 2x^2+9-9=-41-9 \\ 2x^2=-50 \end{gathered}`

Then, divide both sides by 2,

`\begin{gathered} (2x^2)/(2)=-(50)/(2) \\ x^2=-25 \end{gathered}`

The next step is to take the square root to both sides of the equation. Remember that i² = -1,

`\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{-25} \\ x=\pm\sqrt[]{i^2\cdot25} \\ x=\pm5i \end{gathered}`

The solutions to this equation are both imaginary - and complementary, and they are x = 5i and x = -5i