Answer:
The deal with the lowest cost for 14 players is Package 3.
"$25.75 per player no limit on the number of players"
![\begin{gathered} \text{Total cost for 14 players is = 14(\$25.75)} \\ =\text{ \$360.50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x898668kckf4kts9p9tuql9r3ewi8n35kg.png)
Therefore, Package 3 has the best deal for 14 players.
Step-by-step explanation:
Given the table in the attached image.
We want to find the price with the best deal for 14 players.
For deal 1;
$365 for 14 players maximum 14 players
![\text{Total cost for 14 players is = \$365}](https://img.qammunity.org/2023/formulas/mathematics/college/y9ejq0jmnng30eimbntg04uk4zm6aleqzb.png)
For deal 2;
$250 for 10 players, $30 for each additional player limited to 20 players
![\begin{gathered} \text{Total cost for 14 players is = \$250+4(\$30)} \\ =\text{ \$370} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/y7c3wfeqv0y852310y7av15af5h7sxlfr7.png)
For deal 3;
$25.75 per player no limit on the number of players
![\begin{gathered} \text{Total cost for 14 players is = 14(\$25.75)} \\ =\text{ \$360.50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x898668kckf4kts9p9tuql9r3ewi8n35kg.png)
From the deals, the deal with the lowest cost for 14 players is deal 3.
"$25.75 per player no limit on the number of players"
![\begin{gathered} \text{Total cost for 14 players is = 14(\$25.75)} \\ =\text{ \$360.50} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x898668kckf4kts9p9tuql9r3ewi8n35kg.png)
Therefore, Package 3 has the best deal for 14 players.