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(0,8)-10(6,4)-104A. y=-2x+8B. y =y=-x+8O C. y = 8x-2OD. y = 2x + 8

(0,8)-10(6,4)-104A. y=-2x+8B. y =y=-x+8O C. y = 8x-2OD. y = 2x + 8-example-1

1 Answer

4 votes

To find the equation of the line

First find the slope using the formula


m=(y_2-y_1)/(x_2-x_1)

From the points:

(0, 8) (6, -4)

x₁=0 y₁=8 x₂=6 y₂=-4

substitute the values and evaluate


m=(-4-8)/(6-0)
=-(12)/(6)=-2

Next, is to find the intercept

substitute x=0 y=8 and m=-2 into y=mx+ b and solve for intercept b

8 = -2(0) + b

b=8

To form the new equation, substitute m=-2 and b=8 into y=mx+b

y=-2x + 8

User Vaxo Basilidze
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