Consider that the area (A) of a square with side 's' is given by the formula,

Given that the area is 49 sq. meters,

Substitute the values and solve for the side 's' as follows,
![\begin{gathered} s^2=49 \\ s=\sqrt[]{49} \\ s=\pm7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/amcie2ooe7vqiv5f6yke79zxuzfdaaz8q0.png)
But 's' is the side of the square, which cannot be negative.
So we have to neglect the negative value, and consider the positive value,

Thus, the side of the given square is 7 meters .