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Laurent LA RIZZA · Answer 1 · 2023-03-10T00:56:47+0000

The magnitude of the force exerted by Block 2 takes into account the mass of Block 1 because it's above it, so the force must include both masses.

Use Newton's Second Law.

$\Sigma F_y=ma$
$\begin{gathered} N-W=(m_1+m_2)a \\ N-(m_1+m_2)g=(m_1+m_2)a_{} \\ N=(m_1+m_2)(g+a) \end{gathered}$

Use the given magnitudes to find the force N.

$\begin{gathered} N=(2\operatorname{kg}+3\operatorname{kg})(9.8\cdot(m)/(s^2)+1.6\cdot(m)/(s^2)) \\ N=5\operatorname{kg}\cdot11.4\cdot(m)/(s^2) \\ N=57N \end{gathered}$

Therefore, the force exerted by Block 2 is 57 Newtons.

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