Question

A rope pulls a 32.5-kg block upward with a constant acceleration of 5.21 meters per second squared. What is the tension in the rope? (a) 150 N(b) 488 N(c) 624 N(d) 748 N

Answer 1

Free body diagram:

The free body equation is given as,

`T-mg=ma`

Therefore, tension in the rope T is given as,

`T=m(g+a)`

Subsriruring all known values,

`\begin{gathered} T=32.5*(9.81+5.21) \\ =488.15\text{ N} \end{gathered}`

Therefore, the tension in the rope is 488.15 N. Hence, option (b); 488 N is the best choice.