Question

If the volume of the original sample in Part A ( P1 = 472 torr , V1 = 36.0 L ) changes to 56.0 L , without a change in the temperature or moles of gas molecules, what is the new pressure, P2 ?

Answer 1

When we have an expansion or compression process of an ideal gas at constant temperature, we can apply Boyle's law. This law relates pressure and volume and is described by the following equation:

`P_1V_1=P_2V_2`

Where

P1 is the initial pressure in atm, 472torr =0.621atm

V1 is the initial volume in Liters, 36.0L

V2 is the final volume in liters, 56.0L

P2 is the final pressure =?

Now, we clear P2 and replace the known data:

`\begin{gathered} P_2=(P_1V_1)/(V_2) \\ P_2=(0.621atm*36.0L)/(56.0L)=0.399atm \end{gathered}`

P2= 0.399atm=304torr

Answer: The new pressure will be 304 torr