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Can you assist with #7 look ate the finished rest as a guide if necessary

Can you assist with #7 look ate the finished rest as a guide if necessary-example-1

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We know that the segment DP is an angle bisector of angle BDC; this means that angle 1 has to be half angle BDC, that is:


m\angle1=(1)/(2)m\angle BDC

Plugging the expresions given for each angle we have:


\begin{gathered} 6x+6=(1)/(2)(15x) \\ 12x+12=15x \\ 15x-12x=12 \\ 3x=12 \\ x=(12)/(3) \\ x=4 \end{gathered}

Therefore, the value of x is 4

User Morgan Feeney
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