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Two integers have a sum of 0 and a difference of 32. what are the integers?

1 Answer

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Answer:

16 and -16

Step-by-step explanation:

Let's call x the first number and y the second number.

If they have a sum of 0, we can write that:

x + y = 0

On the other hand, if the difference is 32, we can write the equation:

x - y = 32

Now, we have the system of equations:

x + y = 0

x - y = 32

We can add both equations to get:

x + y = 0

x - y = 32

2x + 0 = 32

Then, we can solve for x:

2x = 32

2x/2 = 32/2

x = 16

Finally, we can replace x by 16 and calculate the value of y as:

x + y = 0

16 + y = 0

16 + y - 16 = 0 - 16

y = -16

Therefore, the integers are x = 16 and y = -16

User Hemant Kothiyal
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