498,184 views
12 votes
12 votes
The tiny town of Nemo has three neighborhoods located on a straight line: Neighborhood 1, Neighborhood 2, and Neighborhood 3, with Neighborhood 2 located equidistant between Neighborhood 1 and Neighborhood 3. There is one daycare center, located on Neighborhood 1. There are 10 families residing in each neighborhood, and each family has one child. Each family is willing to pay $70/day for daycare, and prefers daycare closest to its own neighborhood (though at current distances, families will purchase daycare services even if it’s two neighborhoods away). Families are indifferent between any two daycares in the same neighborhood. Suppose that daycare costs $30/day per child to provide. A new daycare center is thinking of opening in Nemo. If both daycares will keep their price at $70/day, which neighborhood should the new daycare open in?

User Walt D
by
2.7k points

1 Answer

14 votes
14 votes

Answer:

Neighborhood 2

Step-by-step explanation:

Based on the information given if NEIGHBORHOOD 2 is located between Neighborhood 1 and Neighborhood 3 which means that in a situation where both daycares decide to keep their price at the amount of $70/day, the neighborhood that the new day care should open in is NEIGHBORHOOD 2 reason been that with NEIGHBORHOOD 2 all the families living in both Neighborhoods 2 and Neighborhoods 3 will be attracted to Neighborhoods 2 and on the other hand won't not be attracted to Neighborhood 1, for the amount of $800/day which is calculated as:

(10 Families *2) * ($70 for day care - $30 per child)

20*40= $800/day

Therefore the neighborhood that the new daycare should open in is NEIGHBORHOOD 2

User Agentfll
by
3.2k points