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Express (2x – 1)(x + 5) - 1x2as a trinomial in standard form.

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The given expression can be expressed in the trinomial in standard form as,


\begin{gathered} (2x-1)(x+5)-(1)/(2)x^2=\lbrack2x(x+5)-1(x+5)\rbrack-(1)/(2)x^2 \\ =\lbrack2x^2+10x-x-5\rbrack-(1)/(2)x^2 \\ =\lbrack2x^2+9x-5\rbrack-(1)/(2)x^2 \\ =(3)/(2)x^2+9x-5 \end{gathered}

Thus, the above expression is the requried trinomial.

User Kerrek SB
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