Surface Area of a Right Traingular Prism is = bh + L(S1 + S2 + h)
from the question given
h = 5,
S1 = 12 = b
S2 = 13
L =10
= bh + L(S1 + S2 + h)
= 12(5) + 10(12 + 13 + 5)
= 60 + 10(30)
=60 + 300
=360
From the shape
The Triangle side Area = 1/2 X B X H
=1/2 X12 X 5 = 30
we have two faces of the triangle = 2x 30 = 60
For the Top side = 10 X 13 = 130
for the base/floor = 12 x 10 = 120
for the back end side = 5 x 10 = 50
Total = 60 + 130 + 120 +50
=360