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Find the equation of the line thatis parallel to y = 2x + 5 and 6contains the point (2,-4).y = [? ]X + [ ]Enter

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The general equation of a line in slope-intercept form is given by:


y=mx+c

Given the equation of a line to be


y=2x+5

Upon comparing the equation to the general line equation, then


\begin{gathered} m=2 \\ c=5 \end{gathered}

Next, to find the equation of the line parallel to the given line

we will use the formula


y-y_1=m(x-x_1)

where


\begin{gathered} m=2 \\ x_1=2 \\ y_1=-4 \end{gathered}


\begin{gathered} y-(-4)=2(x-2) \\ y+4=2x-4 \\ y=2x-4-4 \\ y=2x-8 \end{gathered}

The equation of the line is y=2x -8

User OMGHaveFun
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