Question

What volume in

L

of a 0.724 M Nal solution contains 0.405 mol of Nal ?

Answer 1

`0.5594\ \text{L}`

Step-by-step explanation:

Mol of NaI = 0.405 mol

Molarity of solution = 0.724 M

Molarity is given by

`M=\frac{\text{mol}}{\text{Volume of solution in }NaI}\\\Rightarrow \text{Volume of solution in }NaI=(0.405)/(0.724)\\\Rightarrow \text{Volume of solution in }NaI=0.5594\ \text{L}`

The required volume is
`0.5594\ \text{L}`.