Question

triangles a,b,c was reflected over the x axis and dialated by a scale factor of 3 to create triangle a,b,c shown on the coordinate grid below.

Answer 1

Coordinates of A'B'C':

`\begin{gathered} A^(\prime)(-9,3) \\ B^(\prime)(-3,0) \\ C^(\prime)(0,6) \end{gathered}`

To get coordinates of triangle ABC:

Dilate the triangle A'B'C' by a facor of 1/3:

Rule of dilation:

`P(x,y)\rightarrow P^(\prime)(kx,ky)`

k is the factor of dilation:

Then, you get;

`\begin{gathered} A^(\prime)(-9,3)\rightarrow A^(\doubleprime)((1)/(3)(-9),(1)/(3)(3)) \\ A^(\prime)(-9,3)\rightarrow A^(\prime)^(\prime)(-3,1) \end{gathered}`

Relect over x-axis:

Rule of relection:

`P(x,y)\rightarrow P^(\prime)(x,-y)`

Then, coordiate of point A is:

`A^(\doubleprime)(-3,1)\rightarrow A(-3,-1)`Then, coordinates of A are (-3,-1)