Answer:
the perimeter is 32sqrt(3) yd, or approximately 55.4 yd
Explanation:
A square has 4 congruent sides, so if the length of 1 side is s, the perimeter is 4s. Also, the area of a square is the side squared, or A = s^2.
A = s^2
s^2 = 192 yd^2
Take the square root of both sides.
s = sqrt(192)
s = sqrt(64 * 3)
s = 8sqrt(3)
P = 4s
P = 4 * 8sqrt(3) = 32sqrt(3)
Answer: the perimeter is 32sqrt(3) yd, or approximately 55.4 yd