Question

I don't know how to begin or try this problem

Answer 1

length =24, width =15

1) The best way to tackle this question is by sketching this out:

2) We can think of it as a rectangle whose area is 360yd². Since the farmer has 54 yds we can write out this:

We can set two equations: one evolving the sum of three sides and the other one the area:

`\begin{gathered} 2b+h=54 \\ bh=360 \\ ----- \\ 2b=54-h\Rightarrow b=27-(h)/(2) \\ bh=360 \\ (27-(h)/(2))h=360 \\ \\ 27h-(h^2)/(2)=360 \\ -(h^2)/(2)+27h-360=0 \\ (h^2)/(2)-27h+360=0 \\ h=\frac{27\pm\sqrt[]{(27)^2-4((1)/(2))(360)}}{2((1)/(2))} \\ h=24 \\ --- \\ 2b+24=54 \\ 2b=54-24 \\ 2b=30 \\ b=15 \end{gathered}`